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Answers to Puzzles, part 2
Updated February 4, 2000
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Solutions, part 1
16. My mom went to a flea market and saw plates for $5, spoons for $1, and little paper umbrellas for 5 cents. She spent $100 for 100 items and yes, she bought all three kinds of items. What did she buy? Solution: The easy solution is 100 spoons, but since she had to go and buy some of each item... Let x = #plates, y = #spoons, and z = #umbrellas. Okay, because she spent exactly $100, she must have bought a multiple of 20 of the little umbrellas. This leaves: 5x + y + .05z = 100 for z = 20, 40, 60, 80, ... where x + y + z = 100 and x, y, and z are integers. Start at z=20 and solve this set of equation and you'll get z = 80, x = 1, and y = 19.
17. There are 2 pieces of string. Each piece is made of a different material and are of different lengths. Both pieces of string takes exactly 1hour to burn from 1 end to the other end. The speed of burning is not uniform throughout, so it can burn quickly first than slowly at the end or any random way. If you are given only these 2 pieces of string and a box of matches, how do you measure 45 minutes? The proper solution only requires you to burn the strings. [credit malcolm thompson] Solution: Take one string and light BOTH ends, and light one end of the second string. The first string will burn out completely in 30 minutes. At that time, light the unlit end of the second string. The second string will then burn out in 15 minutes. Total, 45 minutes.
18. Below is a quiz written [supposedly] by Einstein. Supposedly, 98% of the people in the world cannot solve the quiz -- either cannot, or haven't yet been to my page :). Are you among the other 2%? Here you go... Facts:
Solution: This puzzle took me a while to solve and is not that easy to explain. First, make a grid, like so:
1 2 3 4 5
|----------------------------------------
| | | | | | color
|----------------------------------------
| | | | | | country
|----------------------------------------
| | | | | | drink
|----------------------------------------
| | | | | | smoke
|----------------------------------------
| | | | | | pet
|----------------------------------------
Fill out all the obvious clues. Remember, it's as important if you know a box is NOT something or is something. So put that down. Now solve the puzzle!!
#16. From #14 & #9, we know that house #2 is blue. Since from #4, the green house is to the left of the white house, it cannot be house 5 [nothing on its left], or 1 [left of the blue house], so it must be 3 or 4. From #5 & #8, house #4 must be green, so therefore 5 is white, and from #1, 1 is yellow and 3 is red as well as British. We now have all the right colors.
1 2 3 4 5
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|yellow | blue | red | green | white | color
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|norway | | uk | | | country
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| | | milk |coffee | | drink
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|dunhill| | | | | smoke
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| | | | | | pet
|----------------------------------------
Now for the beverages: We know from #8 that 3 drinks milk, and from #5 and above #16 that 4 drinks coffee. House 1 cannot drink tea because of #3, and cannot drink beer because of #12 and #7 and #16. So house 1 drinks water. Therefore from #15, house 2 smokes Blend and from #11 has a horse and must be Danish [cannot be German who smokes Prince, or Swedish who has a dog]. Thus 2 drinks tea and 5 drinks beer.
1 2 3 4 5
|----------------------------------------
|yellow | blue | red | green | white | color
|----------------------------------------
|norway | dane | uk | german| swed | country
|----------------------------------------
| water | tea | milk |coffee | beer | drink
|----------------------------------------
|dunhill| blend | |prince | blue m| smoke
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| | horse | | | | pet
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Now 5, who drinks beer and smokes blue master [#12], must be Swedish, so the dog goes here [#2]. House 4 must be German and smokes Prince because house 3 is already British. Thus 3 smokes Pall Mall and owns a bird [#6]. Because of #10, house 1 has a cat. Therefore, the German in house 4 has the fish. Phew.
1 2 3 4 5
|----------------------------------------
|yellow | blue | red | green | white | color
|----------------------------------------
|norway | dane | uk | german| swed | country
|----------------------------------------
| water | tea | milk |coffee | beer | drink
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|dunhill| blend | pm |prince | blue m| smoke
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| cat | horse | bird | FISH! | dog | pet
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19. Shackleford, Campbell, Garfield, and Colson make up a flight crew -- pilot, copilot, navigator, and engineer, but not necessarily in that order. Using the clues below, find out who holds which job. The clues may or may not be of any use to you.
Solution: This puzzle is considerably easier than the fish one. Still, a grid is helpful: Fill in the obvious clues... #2 4 6 7 & 9 Sh Camp Garf Colson |---------------------------------------- friends? | n w/ co | --- | | n w/ sh | |---------------------------------------- wife? | | | yes | yes | |---------------------------------------- glasses? | no | | | no | |---------------------------------------- job | | | not c/n | | |---------------------------------------- Sh Camp Garf Colson |---------------------------------------- friends? | n w/ co | --- | --- | n w/ sh | |---------------------------------------- wife? | no | engaged | yes | yes | |---------------------------------------- glasses? | no | yes | | no | |---------------------------------------- job | p or co | nav | not c/n | Eng | |----------------------------------------now, from #9 & 10, Campbell is the navigator [unmarried and glasses] so, since the engineer is married, Shackleford cannot be the engineer and so must be the pilot or the copilot. Since Shackleford is not friends with Colson, Colson cannot be the pilot or the copilot [from #1]. Therefore Colson is the engineer.
Sh Camp Garf Colson
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friends? | n w/ co | --- | --- | n w/ sh |
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wife? | no | engaged | yes | yes |
|----------------------------------------
glasses? | no | yes | no | no |
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job | co | nav | Pilot | Eng |
|----------------------------------------
since Garfield cannot be the copilot, Shackleford must be the copilot while Garfield is the pilot. ta da!
20. These are classic IQ type questions from the 11/99 issue of Esquire Magazine. See problem (1) on that link [the visually oriented ones I shall omit here]. 20. These are classic IQ type questions from the 11/99 issue of Esquire Magazine. See problem (1) on that link [the visually oriented ones I shall omit here].
21. Here is a classic riddle, courtesy of ay, domo! In ancient Greece, when the Gods ruled the world, Iganor, the God of bad luck, sentenced a mortal warrior to death. Iganor was a reasonable God and allowed the warrior to choose his method of death. The warrior was allowed to make one statement; if the statement were true, the warrior would be fed to the dragons and if the statement were false, the warrior was to be killed by a poisoned fruit tart! The warrior mulled his predicament over and finally made a statement. After hearing it, Iganor had no choice but to free the warrior. What did the warrior say to save himself? Solution: Essentially, he needs to contradict Iganor's terms witha paradox. He can say, "I will be killed by a poison fruit tart," or, "I will not be fed to the dragons."
22. Here is a straight up math problem, courtesy of tj, domo! A boat leaves a pier and travels UPSTREAM [ie, against the river current] for one mile. There, it passes a log floating on the river heading [obviously] downstream. The boat then keeps traveling for one hour; then turns around and heads back toward the pier where it came from. The boat and the log arrive at the pier simultaneously. Assume that the boat is traveling at a constant engine speed, and that the river is also flowing at a constant speed. How fast is the boat going? What about the river? Solution: The answers are: the river is flowing at ?miles per hour, while it does not matter how fast the boat is moving, as long as it exceeds ?miles per hour. Let's set up the solution: (P)___1 mile___(q)___________(x-y)____________ (P)= pier (q)= where the boat first spots the log x = the neutral speed of the boat y = the speed of the river, and therefore the log The boat first travels 1 mile. It then travels for one more hour. Upstream, its speed would be (x-y) so it travels (x-y) miles. During the time the boat travels that (x-y) distance upstream, the log travels downstream at a speed of y, so it would have moved y miles so is now (1-y) miles away from the pier. Now, the boat & log will take the same time to travel (1 + x - y) and (1 - y) miles respectively. Note that the boat will now travel at x + y miles per hour as it is traveling upstream. So: (1 + x - y) (1 - y) ----------- = ------- (x + y) y y + xy - y^2 = x - xy + y -y^2 x= 2xy y= ? The reason why it doesn't matter what speed the boat is travelling at is because this factor gets canceled out on the return trip. That is, whatever that boat speed is going out, will be the same going back.
Cop/Thief Cop Cop/boy 1 Cop/Thief Dad/boy 2 Dad Dad/Mom Mom Cop/Thief Dad Dad/Mom Mom Mom/girl 1 Cop/Thief Cop/girl 2 Cop Cop/Thief
Happy puzzling.
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