by Le Magicien

This is the project of rechargeable flashlight using a high intensity red Jumbo Led. The main idea is to have a moderate source of light that will be ever at hand, without batteries to replace or light bulbs to change. It may be left plugged in the 110 vac wall outlet, ready for use.

Click on the left to see the main circuit of the flashlight.


When the flashlight is not plugged in a AC outlet, diode D4 prevents any current flow from battery B to Q1. Therefore the circuit is reduced to the scheme shown in Fig 1.

Thus according, the emitter of Q2 transistor is directly connected to the (-) terminal of the battery B and its base is positively polarized through R5. In this way the base-emitter junction of the transistor is directly polarized turning on the collector-emitter junction and allowing current to flow from battery B to ML (Main Led).

When the flashlight is plugged and charging we have the situation depicted in Fig 2. Charging led indicator CL is on while the main led ML is off.

How Q2 is turned off? Note that Q1 is turned on as the base has a positive supply given by R2 and the charging led CL has a 1.9 junction drop (as any other red led) that remains constant, as it behaves as a zener diode. Thus the circuit around Q1 configures a constant current supply.
In order to turn off Q2 we need its base-emitter junction forward drop to be lower than 0.7 volt or even better: to have VbeQ2 negative.
While charging, the measured voltage (red values in Fig 2) at top of voltage divider given by R5 & R6 is 4.7 volt. Supply voltage is aprox 0.7 volts above (due to D4 forward drop), or 5.7 volt. At Q1's collector we have 5.4 - 3.9= 0.8 volts. And the voltage divider sets Q2 base at 0.2 volt.

With these values it's easy to calculate VbeQ2:

VbeQ2 = Vb - Ve (for Q2) and as VeQ2 = VcQ1 = 0.8 volt
VbeQ2 = 0.2 - 0.8 = - 0.5 volt inversely polarized and Q2 remains in cut-off condition.

The basic point here was to calculate the voltage divider values so as to inversely polarize the base-emitter junction of Q2.


This flashlight has the advantage that no bulb will ever burn, also the rechargeable NiCd battery may be of the camera type: 3.9 volt / 110 mAh with a size a little bit bigger than the regular AA batteries. With the current circuit configuration this flashlight will run for 3 to 5 hours and will be fully charged in approximately 6 hours or less.

But you may use a battery pack if you like, just follow the following example to determine new values:

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